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6.25=2x+x^2
We move all terms to the left:
6.25-(2x+x^2)=0
We get rid of parentheses
-x^2-2x+6.25=0
We add all the numbers together, and all the variables
-1x^2-2x+6.25=0
a = -1; b = -2; c = +6.25;
Δ = b2-4ac
Δ = -22-4·(-1)·6.25
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{29}}{2*-1}=\frac{2-\sqrt{29}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{29}}{2*-1}=\frac{2+\sqrt{29}}{-2} $
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